Non Maxima Supression

$I n t ersec t i o n O v er U ni o n (I o U) = (T a r g e t \cap P re d i c t i o n) / (T a r g e t U P re d i c t i o n)$
In our case using BBoxes, it can be modified to,

$I O U (B o x 1, B o x 2) = I n t ersec t i o n_{S} i ze (B o x 1, B o x 2) / U ni o n_{S} i ze (B o x 1, B o x 2)$

Subhaditya's KB